Compare Datetime Arrays

Compare twodatetimearrays. The arrays must be the same size or one can be a scalar.

A = datetime(2013,07,26) + calyears(0:2:6)

A =1x4 datetime array26-Jul-2013 26-Jul-2015 26-Jul-2017 26-Jul-2019

B = datetime(2014,06,01)

B =datetime01-Jun-2014

A < B

ans =1x4 logical array1 00 0

The<operator returns logical1(true) where a datetime inAoccurs before a datetime inB.

Compare adatetimearray to text representing a date.

A >='September 26, 2014'

ans =1x4 logical array0 1 1 1

Comparisons ofdatetimearrays account for the time zone information of each array.

Compare September 1, 2014 at 4:00 p.m. in Los Angeles with 5:00 p.m. on the same day in New York.

A = datetime(2014,09,01,16,0,0,'TimeZone','America/Los_Angeles',...'Format','dd-MMM-yyyy HH:mm:ss Z')

A =datetime01-Sep-2014 16:00:00 -0700

B = datetime(2014,09,01,17,0,0,'TimeZone','America/New_York',...'Format','dd-MMM-yyyy HH:mm:ss Z')

B =datetime01-Sep-2014 17:00:00 -0400

A < B

ans =logical0

4:00 p.m. in Los Angeles occurs after 5:00 p.m. on the same day in New York.

Compare Durations

Compare twodurationarrays.

A = duration([2,30,30;3,15,0])

A =2x1 duration array02:30:30 03:15:00

B = duration([2,40,0;2,50,0])

B =2x1 duration array02:40:00 02:50:00

A >= B

ans =2x1 logical array0 1

Compare a duration array to a numeric array. Elements in the numeric array are treated as a number of fixed-length (24-hour) days.

A < [1; 1/24]

ans =2x1 logical array1 0

Determine if Dates and Time Are Contained Within an Interval

Use theisbetweenfunction to determine whether values in adatetimearray lie within a closed interval.

Define endpoints of an interval.

tlower = datetime(2014,08,01)

tlower =datetime01-Aug-2014

tupper = datetime(2014,09,01)

tupper =datetime01-Sep-2014

创建一个datetimearray and determine whether the values lie within the interval bounded byt1andt2.

A = datetime(2014,08,21) + calweeks(0:2)

A =1x3 datetime array21-Aug-2014 28-Aug-2014 04-Sep-2014

tf = isbetween(A,tlower,tupper)

tf =1x3 logical array1 1 0